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            最全50個Mysql數據庫查詢練習題

             更新時間:2020年12月29日 12:55:40   作者:新宿一次狼  
            這篇文章主要介紹了最全50個數據庫查詢練習題,Mysql數據庫版本,全部都驗證過

            此數據庫查詢語句是網絡上50個數據庫查詢練習題目,網上有些版本是oracle語句寫的,大多數公司還是用免費的mysql數據庫,以下都是mysql版本,全部都有驗證過。

            表名和字段

            –1.學生表
            Student(s#, sname, sage,ssex) –學生編號,學生姓名, 出生年月,學生性別
            –2.課程表
            Course(c#,cname,t#) – –課程編號, 課程名稱, 教師編號
            –3.教師表
            Teacher(t#,tname) –教師編號,教師姓名
            –4.成績表
            Sc(s#,c#,score) –學生編號,課程編號,分數

            測試數據

            用數據庫可視化工具做練習非常方便,推薦使用sqlyog,軟件圖標是一只海豚。

            在新連接種填上本機地址,用戶名,密碼和端口就直接連上mysql。

            所有測試數據如下:

            # --插入學生表測試數據
            INSERT INTO student VALUES('01' , '趙雷' , '1990-01-01' , '男');
            INSERT INTO student VALUES('02' , '錢電' , '1990-12-21' , '男');
            INSERT INTO student VALUES('03' , '孫風' , '1990-05-20' , '男');
            INSERT INTO student VALUES('04' , '李云' , '1990-08-06' , '男');
            INSERT INTO student VALUES('05' , '周梅' , '1991-12-01' , '女');
            INSERT INTO student VALUES('06' , '吳蘭' , '1992-03-01' , '女');
            INSERT INTO student VALUES('07' , '鄭竹' , '1989-07-01' , '女');
            INSERT INTO student VALUES('08' , '王菊' , '1990-01-20' , '女');
            # --插入課程表測試數據
            INSERT INTO course VALUES('01' , '語文' , '02');
            INSERT INTO course VALUES('02' , '數學' , '01');
            INSERT INTO course VALUES('03' , '英語' , '03');
             
            # --插入教師表測試數據
            INSERT INTO teacher VALUES('01' , '張三');
            INSERT INTO teacher VALUES('02' , '李四');
            INSERT INTO teacher VALUES('03' , '王五');
             
            # --插入成績表測試數據
            INSERT INTO sc VALUES('01' , '01' , 80);
            INSERT INTO sc VALUES('01' , '02' , 90);
            INSERT INTO sc VALUES('01' , '03' , 99);
            INSERT INTO sc VALUES('02' , '01' , 70);
            INSERT INTO sc VALUES('02' , '02' , 60);
            INSERT INTO sc VALUES('02' , '03' , 80);
            INSERT INTO sc VALUES('03' , '01' , 80);
            INSERT INTO sc VALUES('03' , '02' , 80);
            INSERT INTO sc VALUES('03' , '03' , 80);
            INSERT INTO sc VALUES('04' , '01' , 50);
            INSERT INTO sc VALUES('04' , '02' , 30);
            INSERT INTO sc VALUES('04' , '03' , 20);
            INSERT INTO sc VALUES('05' , '01' , 76);
            INSERT INTO sc VALUES('05' , '02' , 87);
            INSERT INTO sc VALUES('06' , '01' , 31);
            INSERT INTO sc VALUES('06' , '03' , 34);
            INSERT INTO sc VALUES('07' , '02' , 89);
            INSERT INTO sc VALUES('07' , '03' , 98);

            最后是50個數據庫查詢練習,已經驗證過,是mysql版本的。

            1. 查詢" 01 "課程比" 02 "課程成績高的學生的信息及課程分數

            SELECT * FROM
              (SELECT `s#` AS sno1, `c#`AS cno1, score FROM sc WHERE `c#`=01) a
                LEFT JOIN
              (SELECT `s#` AS sno2, `c#`AS cno2, score FROM sc WHERE `c#`=02) b
                ON a.sno1 = b.sno2
                WHERE a.score > b.score

            1.1 查詢同時存在" 01 "課程和" 02 "課程的情況

            SELECT * FROM
              (SELECT `s#` AS sno1, `c#`AS cno1, score FROM sc WHERE `c#`=01) a
                LEFT JOIN
              (SELECT `s#` AS sno2, `c#`AS cno2, score FROM sc WHERE `c#`=02) b
                ON a.sno1 = b.sno2
                WHERE sno2 IS NOT NULL

            1.2 查詢存在" 01 "課程但可能不存在" 02 "課程的情況(不存在時顯示為 null )

            SELECT * FROM
              (SELECT `s#` AS sno1, `c#`AS cno1, score FROM sc WHERE `c#`=01) a
                LEFT JOIN
              (SELECT `s#` AS sno2, `c#`AS cno2, score FROM sc WHERE `c#`=02) b
                ON a.sno1 = b.sno2

            1.3 查詢不存在" 01 "課程但存在" 02 "課程的情況

            SELECT * FROM
                sc WHERE `c#`='02' AND `s#` NOT IN (SELECT `s#` FROM sc WHERE `c#`='01')

            2. 查詢平均成績大于等于 60 分的同學的學生編號和學生姓名和平均成績

            SELECT a.`s#`,b.`sname`, a.avg_score FROM 
              (SELECT `s#` ,AVG(score) AS avg_score FROM sc GROUP BY `s#`) AS a
                LEFT JOIN student AS b
                ON a.`s#` = b.`s#`
                WHERE a.avg_score >=60

            3. 查詢在 SC 表存在成績的學生信息

            SELECT * FROM student WHERE `s#` IN (SELECT DISTINCT `s#` FROM sc)

            4. 查詢所有同學的學生編號、學生姓名、選課總數、所有課程的總成績(沒成績的顯示為 NULL )

            SELECT `s#` ,sname , course_num , score_sum FROM 
              (SELECT `s#`, sname FROM student ) AS a
                LEFT JOIN
              (SELECT `s#` AS sno ,COUNT(`c#`) AS course_num ,SUM(score) AS score_sum FROM sc GROUP BY sno) AS b
                ON a.`s#` = b.sno
            

            4.1 查有成績的學生信息

            # 在最外面一層select的時候,不可以用函數
            # 如果兩張表連接之后,有相同的字段,這時候select就需要把其中一個字段改名

            SELECT `s#` ,sname , course_num , score_sum FROM 
              (SELECT `s#`, sname FROM student ) AS a
                LEFT JOIN
              (SELECT `s#` AS sno ,COUNT(`c#`) AS course_num ,SUM(score) AS score_sum FROM sc GROUP BY sno) AS b
                ON a.`s#` = b.sno
                WHERE course_num IS NOT NULL

            5. 查詢「李」姓老師的數量

            SELECT COUNT(*) FROM teacher WHERE tname LIKE '李%'

            6. 查詢學過「張三」老師授課的同學的信息

            # 張三老師是01號
            SELECT * FROM student WHERE `s#` IN 
              (SELECT `s#` FROM sc WHERE `c#` =
                (SELECT `c#` FROM course WHERE `t#` = 
                  (SELECT `t#` FROM teacher WHERE tname='張三')))

            # 7. 查詢沒有學全所有課程的同學的信息

            SELECT `s#`,COUNT(`c#`) AS course_num FROM sc GROUP BY `s#`
                HAVING course_num < (SELECT COUNT(*) FROM course)

            # 8. 查詢至少有一門課與學號為"01"的同學所學相同的同學的信息

            SELECT * FROM student WHERE `s#` IN 
              (SELECT DISTINCT `s#` FROM sc WHERE `c#` IN
                (SELECT `c#` FROM sc WHERE `s#`=01))
              AND `s#`!= 01

            # 9. 查詢和"01"號的同學學習的課程完全相同的其他同學的信息

            SELECT `s#` FROM 
              (SELECT * FROM sc 
                LEFT JOIN 
              (SELECT `c#` AS cno FROM sc WHERE `s#` =01) a
                ON sc.`c#` = a.cno) AS b
            GROUP BY `s#`    
            HAVING COUNT(b.`s#`) = (SELECT COUNT(`c#`) AS cno FROM sc WHERE `s#` =01)

            # 10. 查詢沒學過"張三"老師講授的任一門課程的學生姓名

            # 張三是01
            # 01老師是教數學,c#是02
            SELECT * FROM student WHERE `s#` NOT IN 
              (SELECT DISTINCT `s#` FROM sc WHERE `c#` IN 
                (SELECT `c#` FROM course WHERE `t#` IN 
                  (SELECT `t#` FROM teacher WHERE tname = '張三')))

            # 11. 查詢兩門及其以上不及格課程的同學的學號,姓名及其平均成績

            SELECT `s#`, sname, avg_score FROM 
              (SELECT `s#`, sname FROM student WHERE `s#` IN
                (SELECT a.`s#` FROM 
                  (SELECT `s#`,COUNT(`c#`) AS num FROM sc WHERE score <60 GROUP BY `s#`) a
                  WHERE num >=2)) AS b
                LEFT JOIN
              (SELECT `s#` AS sno ,AVG(score) AS avg_score FROM sc GROUP BY `s#`) AS c
                ON b.`s#` = c.sno

            # 12. 檢索" 01 "課程分數小于 60,按分數降序排列的學生信息

            SELECT `s#`, sname, score FROM 
               student AS a
                LEFT JOIN 
              (SELECT `s#` AS sno,`c#`,score FROM sc WHERE `c#`= 01 AND score <60 )b
                ON a.`s#`= b.sno
              WHERE score IS NOT NULL
              ORDER BY score DESC

            # 13. 按平均成績從高到低顯示所有學生的所有課程的成績以及平均成績

            SELECT `s#` ,AVG(score) AS avg_score FROM sc GROUP BY `s#` ORDER BY avg_score DESC

            # 14. 查詢各科成績最高分、最低分和平均分:
            # 以如下形式顯示:課程 ID,課程 name,最高分,最低分,平均分,及格率,中等率,優良率,優秀率
            # 及格為>=60,中等為:70-80,優良為:80-90,優秀為:>=90
            # 要求輸出課程號和選修人數,查詢結果按人數降序排列,若人數相同,按課程號升序排列

            SELECT DISTINCT a.`c#`,cname,最高分,最低分,平均分,及格率,中等率,優良率,優秀率 FROM sc a
            LEFT JOIN course ON a.`c#`=course.`c#`
            LEFT JOIN (SELECT `c#`, MAX(score)最高分, MIN(score)最低分, AVG(score)平均分 FROM sc GROUP BY `c#`)b ON a.`c#`=b.`c#`
            LEFT JOIN (SELECT `c#`, ROUND( r1 /cnt * 100, 2 ) AS 及格率 FROM
              (SELECT `c#`, (SUM(CASE WHEN score >=60 THEN 1 ELSE 0 END)*1.00) AS r1 , COUNT(*) AS cnt FROM sc GROUP BY `c#`) c1) c ON a.`c#`=c.`c#`
            LEFT JOIN (SELECT `c#`, ROUND( r2 /cnt * 100, 2 ) AS 中等率 FROM
              (SELECT `c#`, (SUM(CASE WHEN score >=70 AND score<80 THEN 1 ELSE 0 END)*1.00) AS r2 , COUNT(*) AS cnt FROM sc GROUP BY `c#`) d1) d ON a.`c#`=d.`c#`  
            LEFT JOIN (SELECT `c#`, ROUND( r3 /cnt * 100, 2 ) AS 優良率 FROM
              (SELECT `c#`, (SUM(CASE WHEN score >=80 AND score<90 THEN 1 ELSE 0 END)*1.00) AS r3 , COUNT(*) AS cnt FROM sc GROUP BY `c#`) e1) e ON a.`c#`=e.`c#`
            LEFT JOIN (SELECT `c#`, ROUND( r4 /cnt * 100, 2 ) AS 優秀率 FROM
              (SELECT `c#`, (SUM(CASE WHEN score >=90 THEN 1 ELSE 0 END)*1.00) AS r4 , COUNT(*) AS cnt FROM sc GROUP BY `c#`) f1) f ON a.`c#`=f.`c#`
            

            # 15. 按各科成績進行排序,并顯示排名, Score 重復時保留名次空缺

            # mysql中沒有rank()函數
            # 這種是重復時候保留名次,所以最后名次和人數是一樣的
            SELECT `s#`, `c#`, score, rank FROM
            (SELECT `s#`, `c#`, score,
            @currank := IF(@prevrank = score, @currank, @incrank) AS rank, 
            @incrank := @incrank + 1, 
            @prevrank := score
            FROM sc , (
            SELECT @currank :=0, @prevrank := NULL, @incrank := 1
            ) r 
            ORDER BY score DESC) s

            # 15.1 按各科成績進行排序,并顯示排名, Score 重復時合并名次

            # 這種是當有重復名次的時候變成只有一個名次,所以排名的數量會變少
            SELECT `s#`, `c#`, score, 
            CASE 
            WHEN @prevrank = score THEN @currank 
            WHEN @prevrank := score THEN @currank := @currank + 1
            END AS rank
            FROM sc, 
            (SELECT @currank :=0, @prevrank := NULL) r
            ORDER BY score DESC

            # 16.  查詢學生的總成績,并進行排名,總分重復時保留名次空缺

            # from后面不需要加表的別名
            SELECT `s#`, sum_score, rank FROM
            (SELECT `s#`, sum_score,
            @currank := IF(@prevrank = sum_score, @currank, @incrank) AS rank, 
            @incrank := @incrank + 1, 
            @prevrank := sum_score
            FROM 
            (SELECT `s#`, SUM(score) AS sum_score FROM sc GROUP BY `s#`) c , 
            (SELECT @currank :=0, @prevrank := NULL, @incrank := 1) r 
            ORDER BY sum_score DESC) s

            # 16.1 查詢學生的總成績,并進行排名,總分重復時不保留名次空缺

            SELECT c.*,
            CASE 
            WHEN @prevrank = c.sum_score THEN @currank 
            WHEN @prevrank := c.sum_score THEN @currank := @currank + 1
            END AS rank
            FROM 
            (SELECT a.`s#`,a.sname,SUM(score) AS sum_score
            FROM (student AS a RIGHT JOIN sc AS b ON a.`s#` = b.`s#`) 
            GROUP BY a.`s#` ) c , 
            (SELECT @currank := 0 , @prevrank :=NULL ) d 
            ORDER BY sum_score DESC

            # 17. 統計各科成績各分數段人數:課程編號,課程名稱,[100-85],[85-70],[70-60],[60-0] 及所占百分比

            SELECT a.`c#` , b.cname, 
              SUM(CASE WHEN score >=85 AND score <=100 THEN 1 ELSE 0 END ) '[100-85]',
              SUM(CASE WHEN score >=85 AND score <=100 THEN 1 ELSE 0 END )*1.00/COUNT(*) AS '[100-85]percent',
                SUM(CASE WHEN score < 85 AND score >= 70 THEN 1 ELSE 0 END ) '(85-70]',
                SUM(CASE WHEN score < 85 AND score >= 70 THEN 1 ELSE 0 END )*1.00/COUNT(*) AS '(85-70]percent',
                SUM(CASE WHEN score < 70 AND score >= 60 THEN 1 ELSE 0 END ) '(70-60]',
                SUM(CASE WHEN score < 70 AND score >= 60 THEN 1 ELSE 0 END )*1.00/COUNT(*) AS '(85-70]percent',
                SUM(CASE WHEN score < 60 AND score >= 0 THEN 1 ELSE 0 END ) '(60-0]',
                SUM(CASE WHEN score < 60 AND score >= 0 THEN 1 ELSE 0 END )*1.00/COUNT(*) AS '(85-70]percent',
                COUNT(*) AS counts
            FROM sc a LEFT JOIN course b ON a.`c#` = b.`c#`
            GROUP BY `c#`

            # 18. 查詢各科成績前三名的記錄

            SELECT * FROM sc a WHERE 
              (SELECT COUNT(*) FROM sc WHERE `c#`=a.`c#` AND score>a.score)<3 
              ORDER BY a.`c#`, a.score DESC;

            # 19. 查詢每門課程被選修的學生數

            SELECT `c#`, COUNT(`s#`) FROM 
            (SELECT `s#`,`c#` FROM sc ORDER BY `c#`)a
            GROUP BY `c#` 
            
            SELECT  a.`c#` , b.cname ,COUNT(*) AS num FROM sc a LEFT JOIN course b ON a.`c#` = b.`c#`
            GROUP BY a.`c#`;
            

            # 20. 查詢出只選修兩門課程的學生學號和姓名

            SELECT a.`s#`, a.sname ,cnt FROM 
            student a
            LEFT JOIN 
            (SELECT `s#`,COUNT(`c#`) AS cnt FROM sc GROUP BY `s#`) b
            ON a.`s#`=b.`s#`
            WHERE cnt=2

            # 21. 查詢男生、女生人數

            SELECT ssex,COUNT(ssex) FROM student GROUP BY ssex

            # 22. 查詢名字中含有「風」字的學生信息

            SELECT * FROM student WHERE sname LIKE '%風%'

            # 23. 查詢同名同性學生名單,并統計同名人數

            SELECT a.*,b.同名人數 FROM student a
            LEFT JOIN (SELECT sname,ssex,COUNT(*) AS 同名人數 FROM student GROUP BY sname,ssex)b 
            ON a.sname=b.sname AND a.ssex=b.ssex
            WHERE b.同名人數>1

            # 24. 查詢 1990 年出生的學生名單

            SELECT * FROM student WHERE YEAR(sage) = 1990

            # 25. 查詢每門課程的平均成績,結果按平均成績降序排列,平均成績相同時,按課程編號升序排列

            SELECT `c#`, ROUND(AVG(score),2) AS avg_score FROM sc GROUP BY `c#` ORDER BY `c#` ASC

            # 26. 查詢平均成績大于等于 85 的所有學生的學號、姓名和平均成績

            SELECT c.`s#`,sname ,avg_score FROM
            (student c 
            LEFT JOIN
            (SELECT `s#`, avg_score FROM 
            (SELECT `s#` ,ROUND(AVG(score),2) AS avg_score FROM sc 
            GROUP BY `s#` ORDER BY avg_score DESC)a 
            WHERE avg_score >=85) b
            ON c.`s#` =b.`s#`)
            WHERE avg_score IS NOT NULL

            # 27. 查詢課程名稱為「數學」,且分數低于 60 的學生姓名和分數

            SELECT a.`s#`,a.sname,b.math, b.score FROM
            student a
            LEFT JOIN
            (SELECT `s#`,`c#` AS math ,score FROM sc WHERE `c#` IN 
              (SELECT `c#` FROM course WHERE cname = '數學')
              AND sc.score <60) b
            ON a.`s#`=b.`s#`
            WHERE b.score IS NOT NULL 

            # 28. 查詢所有學生的課程及分數情況(存在學生沒成績,沒選課的情況)

            SELECT a.`s#`,a.`sname`,a.`sage`,a.`ssex`,b.`c#`,b.score FROM 
            student a LEFT JOIN sc b ON a.`s#` = b.`s#`
            LEFT JOIN course c ON c.`c#` = b.`c#`

            # 29. 查詢任何一門課程成績在 70 分以上的姓名、課程名稱和分數

            SELECT a.`s#`,a.`sname`,a.`sage`,a.`ssex`,b.`c#`,b.score FROM 
            student a 
            LEFT JOIN 
            (SELECT `s#`,`c#`,score FROM sc WHERE score >70) b ON a.`s#`=b.`s#`
            LEFT JOIN course c 
            ON c.`c#`=b.`c#`
            WHERE score IS NOT NULL

            # 30. 查詢不及格的課程

            SELECT * FROM sc WHERE score < 60

            # 31. 查詢課程編號為 01 且課程成績在 80 分以上的學生的學號和姓名

            SELECT a.`s#`, a.sname ,b.score FROM 
              student a
                LEFT JOIN
              (SELECT * FROM sc WHERE `c#`='01' AND score >= 80) b
                ON a.`s#` = b.`s#`
              WHERE score IS NOT NULL

            # 32. 求每門課程的學生人數

            SELECT `c#`,COUNT(`c#`) FROM sc GROUP BY `c#`

            # 33. 成績不重復,查詢選修「張三」老師所授課程的學生中,成績最高的學生信息及其成績

            SELECT a.`s#`, a.`sname` ,b.`c#`, b.max_score FROM
            student a
            LEFT JOIN
            (SELECT `s#` AS sid,`c#` ,MAX(score) AS max_score FROM sc WHERE `c#` IN 
              (SELECT `c#` FROM course WHERE `t#` IN 
                (SELECT `t#` FROM teacher WHERE tname = '張三'))) b
            ON a.`s#`=b.sid
            WHERE max_score IS NOT NULL

            # 34. 成績有重復的情況下,查詢選修「張三」老師所授課程的學生中,成績最高的學生信息及其成績

            SELECT * FROM
            (SELECT dd.*,
            CASE 
            WHEN @prevrank = dd.score THEN @currank 
            WHEN @prevrank := dd.score THEN @currank := @currank + 1
            END AS rank
             FROM (SELECT a.*,b.score FROM
            student a 
            LEFT JOIN sc b ON a.`s#` = b.`s#`
            LEFT JOIN course c ON b.`c#` = c.`c#`
            LEFT JOIN teacher d ON c.`t#` = d.`t#` WHERE d.tname = '張三' ) dd,(SELECT @currank := 0 , @prevrank :=NULL ) ff 
            ORDER BY score DESC) AS dddddddd
            WHERE rank = 1;

            # 35. 查詢不同課程成績相同的學生的學生編號、課程編號、學生成績

            SELECT DISTINCT a.`s#`, a.`c#`, a.score FROM sc AS a JOIN sc AS b 
            WHERE a.`c#` != b.`c#` AND a.score = b.score AND a.`s#` != b.`s#`
            ORDER BY a.`s#`, a.`c#`, a.score

            # 36. 查詢每門功課成績最好的前兩名

            # 此題和18題相同
            SELECT * FROM sc a WHERE 
              (SELECT COUNT(*) FROM sc WHERE `c#`=a.`c#` AND score>a.score)<2 
              ORDER BY a.`c#`, a.score DESC;

            # 37. 統計每門課程的學生選修人數(超過 5 人的課程才統計)

            # 要求輸出課程號和選修人數,查詢結果按人數降序排列,若人數相同,按課程號升序排列 
            SELECT a.`c#`, COUNT(*) AS num FROM 
            course a LEFT JOIN sc b ON a.`c#` = b.`c#`
            GROUP BY a.`c#` HAVING num > 5
            ORDER BY num,a.`c#`

            # 38. 檢索至少選修兩門課程的學生學號

            SELECT DISTINCT`s#`,COUNT(`c#`) AS num FROM sc GROUP BY `s#` HAVING num >=2

            # 39. 查詢選修了全部課程的學生信息

            SELECT * FROM 
              (SELECT `s#`,COUNT(*) AS num FROM sc GROUP BY `s#` ) b
              WHERE num = (SELECT COUNT(*) FROM course)

            # 40. 查詢各學生的年齡,只按年份來算

            SELECT *, YEAR(NOW()) - YEAR(sage) AS age FROM student

            # 41. 查詢本周過生日的學生

            SELECT * FROM
            (SELECT * , WEEK(sage), MONTH(sage),DAY(sage),
            WEEK(STR_TO_DATE(CONCAT_WS(',',YEAR(NOW()),MONTH(sage),DAY(sage)),'%y,%m,%d')) AS w FROM student) a
            WHERE w = WEEK(NOW())

            # 42. 查詢下周過生日的學生

            SELECT * FROM
            (SELECT * , WEEK(sage), MONTH(sage),DAY(sage),WEEK(NOW()),
            WEEK(STR_TO_DATE(CONCAT_WS(',',YEAR(NOW()),MONTH(sage),DAY(sage)),'%y,%m,%d')) AS w FROM student) a
            WHERE w + 2 = WEEK(NOW())

            # 43. 查詢本月過生日的學生

            SELECT * , MONTH(sage),MONTH(NOW()) FROM student
            WHERE MONTH(sage) = MONTH(NOW())

            # 44. 查詢下月過生日的學生

            SELECT * , MONTH(sage),MONTH(NOW()) FROM student
            WHERE MONTH(sage) = MONTH(NOW()) + 1

            到此這篇關于最全50個Mysql數據庫查詢練習題的文章就介紹到這了,更多相關Mysql數據庫查詢內容請搜索腳本之家以前的文章或繼續瀏覽下面的相關文章希望大家以后多多支持腳本之家!

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